<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[1 hour resolution with getMeteogramForecastData]]></title><description><![CDATA[<p dir="auto">I've just signed up for premium and set my forecast resolution to 1 hour which works fine in the browser.  I sort of assumed that this would also cause getMeteogramForecastData() to return the data in 1 hour steps instead of 3 hour steps but it does not.<br />
The documentation for getMeteogramForecastData() does elude to the possibility of passing additional parameters but is not really very helpful.<br />
Please can someone tell me if there a way of asking for and getting 1 hour time steps from getMeteogramForecastData()?  If not why not?<br />
Thanks.</p>
]]></description><link>https://community.windy.com/topic/37461/1-hour-resolution-with-getmeteogramforecastdata</link><generator>RSS for Node</generator><lastBuildDate>Mon, 14 Sep 2026 08:36:04 GMT</lastBuildDate><atom:link href="https://community.windy.com/topic/37461.rss" rel="self" type="application/rss+xml"/><pubDate>Tue, 05 Nov 2024 19:06:43 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to 1 hour resolution with getMeteogramForecastData on Tue, 05 Nov 2024 21:35:38 GMT]]></title><description><![CDATA[<p dir="auto">OK, worked it out by looking in fetch.d.ts...<br />
const latLonStep: LatLonStep = { lat:_loc.lat, lon:_loc.lon, step:1};<br />
getMeteogramForecastData(_model, latLonStep).then((meteogramForecast) =&gt; {<br />
_meteogramForecast = meteogramForecast;<br />
updateSounding();<br />
});</p>
]]></description><link>https://community.windy.com/post/202711</link><guid isPermaLink="true">https://community.windy.com/post/202711</guid><dc:creator><![CDATA[tomA27]]></dc:creator><pubDate>Tue, 05 Nov 2024 21:35:38 GMT</pubDate></item></channel></rss>