Topics created by vicb

I was able to solve this using

The less mixins .mobile(), .desktop(), ...

The root scope variables isMobile, ...

I have just seen that the webcams are online.
Thanks !

@vicb Creating plugin API and plugin sandboxing would solve this, but it is quite complex project with unsure result. Yes, javascript has an access to Cordova and Cordova has an access via its plugins to many native functions. iOS is quite safe, because user has to confirm (face id, password) any try to access his/her private data. Android, especially in some older versions, is totaly unsecured.

@vicb

I ask as I tried multiple ways but could not reproduce a time offset like your graphic displays.

@vicb Hi, thank you for reporting! It seems that the data is not divided by the gravitational constant. We will fix it.

I ended up loading detail-render instead and it fixed my issue.

Thanks !

Works great now. Thanks you so much.

Hmm it seems like a bug. Fav can be type station, fav, airport.

Will check

Thx for reporting

Thanks @ivo

So the "better" way to retrieve favorites is

import favs from "@windy/favs"; // or // var favs = W.require('favs');

Then

favs.getAll();

returns:

{ "34.492/-119.702": {key: "34.492/-119.702", lat: 34.491843, lon: -119.702396, name: "Santa Barbara", type: "fav", …}, "36.768/-119.098": {key: "36.768/-119.098", lat: 36.768385, lon: -119.097719, name: "Dunlap", type: "fav", …}, … }

and

favs.getArray();

returns:

[ {key: "37.514/-121.882", lat: 37.513810842731, lon: -121.88215255737303, name: "Mission Peak", type: "fav", …}, {key: "37.365/-122.246", lat: 37.3650410873092, lon: -122.24594593048094, name: "Windy Hill", type: "fav", …}, {key: "34.492/-119.702", lat: 34.491843534372784, lon: -119.70239639282227, name: "Santa Barbara", type: "fav", …}, … ]

@tomasz-w Hello, image upload size has a limit, try to upload a smaller picture.

Thanks !

I use the sfc temp +3 degree for now as an approx - probably too much in the morning or when the cloud cover is important.

The surface temperature reported by the model does not seem to work better (I may want to give it an another try later).

Does it answer your question or is the question more about the temperature gradient ?